Four identical metallic spheres with charges of +3.0 pC, +7.8 ?C,-1.4 ??. and-1.

Question

Four identical metallic spheres with charges of +3.0 pC, +7.8 ?C,-1.4 ??. and-1.2 pC are placed on a piece of paper. The paper is lifted on all corners so that the spheres come into contact with each other simultaneously. The paper is then flattened so that the metallic spheres become separated (a) What is the resulting charge on each sphere? 2.05 HC (b) How many excess or absent electrons (depending on the sign of your answer to part (a)) correspond to the resulting charge on each sphere? 27*10 11X What is the charge of an electron/proton? electrons are absent

Explanation / Answer

b) Charge is positive, so there is absence of electrons..

So, ne = 2.05X10-6C

or, n(1.6X10-19 C) = 2.05X10-6C

or, n = 1.28125X1013 ... number of absent electrons..

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