1. Consider the following collision: Box 1 of mass m, moving to the right with s
ID: 2032638 • Letter: 1
Question
1. Consider the following collision: Box 1 of mass m, moving to the right with speed v, collides with Box 2 of mass 3m, initially at rest. Immediately after the collision, Box 1 is moving left with speed v/2 and Box 2 is moving right with speed v/2. What can you say about the total momentum and total kihetic energy (KE) during this collision? 3m v/2 rest BEFORE AFTER A) Both total momentum and total KE are conserved. B) Neither total momentum, nor total KE are conserved. C Total momentum is conserved, but total KE decreased. D) Total momentum is conserved, but total KE increased. E Total KE is conserved, but total momentum was not. 2. Two sumo wrestlers are labeled 1 and 2. Both are trained to lift weights firom the Boor of a gym to a high bench. At its maximum power setting power P. wrestler 1 is capable of lifting a mass mi, through a height hi. in a time t. Wrestler 2, at its maximum power P2, can lift twice the mass of wrestler 1, through the same height, but it takes twice as long. How do the power outputs of wrestlers 1 and 2 compare? 3. A wrench exerts a torque of 10.2 NM on a hexagonal bolt. If the force on the end of the wrench is 22 N and it makes an angle of 70° with respect to the handle, what is the distance, or moment arm, from the center of the bolt to the point at which the force is applied? A) 0.36m B)0.49m C)20.67N D) 89.8 cm E) None of theseExplanation / Answer
Q1.
total momentum(considering direction to the right to be positive):
before collision=3*m*0+m*v=m*v
after collision=3*m*(v/2)-m*(v/2)
=m*v
hence momentum is conserved.
kinetic energy:
before collision=0.5*m*v^2
after collision=0.5*m*(v/2)^2+0.5*3*m*(v/2)^2
=0.5*m*v^2
hence KE is also conserved.
hence option A is correct.
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