Homework 6 Begin Date: 3/9/2018 12:00:00 AM Due Date: 3/28/2018 11:59:00 PM End
ID: 2032650 • Letter: H
Question
Homework 6 Begin Date: 3/9/2018 12:00:00 AM Due Date: 3/28/2018 11:59:00 PM End Date: 3/28/2018 11:59:00 PM (6%) Problem 12: A child of mass m = 29 kg slides down a slide of height h = 2.8 m without friction. Let gravitational potential energy be zero at ground level. Randomized Variables m- 29 kg h 2.8 m 33% Part (a) Write an expression for the child's total mechanical energy, E, at the top of the slide Dedu Poten Subm Atten 4 5 6 detai 0 Hint I give up! Hints:2% deduction per hint. Hints remaining:3 Feedback: deduction per feedback. Submission History Answer Hints Feedback Totals 33% Part (b) Calculate the change in the child's potential energy AU-Uground-Uiop in Joules from the top to the bottom of the slide at grExplanation / Answer
Solution:
a) Total Energy = kinetic energy + potential energy
=> T.E = 0 + m* g * h
=> T.E = m * g * h
b) Change in potential energy
=> Uground - U top
=> 0 - mgh
=> - 29 * 9.8 * 2.8
=> -795.76 J
So, Change in potential energy = -795.76 J
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