The current loop in Figure 9 forms a right-angled triangle. The loop carries a c

Question

The current loop in Figure 9 forms a right-angled triangle. The loop carries a current I. A uniform magnetic field is directed perpendicular to one edge of the loop. The angle ? in Figure 9 is 392, L has a length of 1.2 m, and the magnetic field strength has a magnitude of 1.6 T. Figure 9 (a) What is the force on the part of the loop parallel (b) What is the sum of the forces on the remaining to the magnetic field? two segments of the loop? (Hint: Write the length of each segment in terms of ? and L, and then use trigonometry.) (c) What can you conclude about the magnetic force on a closed loop in a uniform magnetic field?

Explanation / Answer

a) zero force on the part parallel to magnetic field
F= iLB *Sin(theta)   
theta (angle between current and magnetic field )= 0 so force = 0

b) Force on perpendicular segment = iBL*tan(theta) theta is angle of triangle  
Force  direction out of the page

force on third segment = iBL*tan(theta)
force direction into the page   

c) net force on closed loop is always zero in a uniform magnetic field  

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