number two Dashboard HW#10 C Q. A Ball Rolls Without slippin www.webassign.net/w
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number two
Dashboard HW#10 C Q. A Ball Rolls Without slippin www.webassign.net/web/Student/Assignment-Responses/submit?depz 17876967#02 :A?WebAssign ?Mathway l Math Pr. VHL Central | Course WebcoMTM 2.0 Imported From IE D UCF login Would you like to translate it? 2. 1/3 points | Previous Answers SerPSE9 10.P003.WI. ::: Apps America-... at LIra D Cengage Other Bookmarks A This page is in English Nope Translate Never translate English OptionsX My NotesAsk Your Teacher During a certain time interval, the angular position of a swinging door is described by ? = 4.99 + 10.9t + 2.05t2, where ? is in radians and t is in seconds. Determine the angular position, angular speed, and angular acceleration of the door at the following times. (a) t = 0 rad ?= 10.9 rad/s -4.20 Calculus methods can be used to determine the velocity and acceleration from ?(t), rad/s2 (b) t 3.01 s rad rad/s rad/s2 Need Help? Watch It Save Progress Practice Another Version 3. 1/1 points | Previous Answers SerPSE9 10.P.005.WI. My NotesAsk Your Teacher A wheel starts from rest and rotates with constant angular acceleration to reach an angular speed of 12.5 rad/s in 3.07 s. (a) Find the magnitude of the angular acceleration of the wheel. 4.072 rad/s2 (b) Find the angle in radians through which it rotates in this time interval. 19.19 rad Need Help? Watch It 4. 3/3 points | Previaus Answers SerPSE9 10.P.017.WI. My Notes Ask Your TeacherExplanation / Answer
(Theta = T, omega = w & alpha = a)
2A
T = 4.99 + 10.9t + 2.05t^2
angular velocity is given by:
w = dT/dt = 0 + 10.9*1 + 4.10*t
angular acceleration is given by:
a = dw/dt = 0 + 0 + 4.10
Now at t = 0
T = 4.99 + 10.9*0 + 2.05*0^2 = 4.99 rad
w = 0 + 10.9 + 4.10*0 = 10.9 rad/sec
a = 0 + 0 + 4.10 = 4.10 rad/sec^2
At t = 3.01 sec
T = 4.99 + 10.9*3.01 + 2.05*3.01^2 = 56.37 rad
w = 0 + 10.9 + 4.10*3.01 = 23.24 rad/sec
a = 0 + 0 + 4.10 = 4.10 rad/sec^2
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