As part of a camival game, a 0.553-kg ball is thrown at a stack of 15.8-cm tall,

Question

As part of a camival game, a 0.553-kg ball is thrown at a stack of 15.8-cm tall, 0.343-kg objects and hits with a perfectly horizontal velocity of 10.8 m/s. Suppose the ball strikes the topmost object as shown to the right. Immediately after the collision, the ball has a horizontal velocity of 4.35 m/s in the same direction, the topmost object now has an anqular velocity of 5.23 rad/s about its center of mass and all the objects below are undisturbed. If the object's center of mass is located 11.1 cm below the point where the ball hits, what is the moment of inertia of the object about its center of mass? Number kg. m2 What is the center of mass velocity of the tall object immediately after it is struck? Number m/ s

Explanation / Answer

a)

By Conservation of angular momentum

mVor =mV1r +IW

0.553*10.8*0.111 =0.553*4.35*0.111+I*5.23

I=0.0757 Kg-m2

b)

By Conservation of linear momentum

0.553*10.8=0.553*4.35+0.343*v

V=10.4 m/s

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