PRINTER VERSION BACK NECT Chapter 09, Problem 63 Your answer is partially correc

Question

PRINTER VERSION BACK NECT Chapter 09, Problem 63 Your answer is partially correct. Try again. 3 at www.wiley.com/college/cutnell illustrates one way of solving a problem similar to this one. A thin rod has a length of 0.177 m a moment of inertia of 1.13 x 103 kgm2. A bug standing on the axis decides to crawl out to the other end of the rod. When the bug Cwhose mass is 5 Interactive Solution 9.6 and rotates in a circle on a frictionless tabletop. The axis is perpendicular x 103 kg) gets where it's going, what is the change in the angular velocity of the rod? Number[.044 the tolerance is +/-2% Click if you would like to Show Work for this question: Open Show Work to the length of the rod at one of its ends. The rod has an angular velocity of 0.734 Units T rad/s

Explanation / Answer

Given:
thin rod
? length of 0.177 m
? angular velocity of 0.734 rad/s
? moment of inertia of 1.13 x 10?³ kg · m2

bug : mass = 5 x 10?³ kg

When the bug arrives at the end of the rod, it adds up to the initial inertia.

new inertia = 1.13 x 10?³ kg*m² + [5 x 10?³ kg*(0.177m)²]
new inertia = 1.2866 x 10?³

initial inertia * angular velocity = new inertia * angular velocity
1.13 x 10?³ kg*m² * 0.734 rad/s = 1.2866 x 10?³ * angular velocity
(1.13 x 10?³ kg*m² * 0.734 rad/s) / 1.2866 x 10?³ = angular velocity
0.644 rad/s = angular velocity

The angular velocity of the rod after the bug reach its end is 0.24 rad/s

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