(5%) Problem 6: A wire carrying a 45 A current passes between the poles of a str
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(5%) Problem 6: A wire carrying a 45 A current passes between the poles of a strong magnet so that it is perpendicular to the field and experiences a 2.14 N force on the 3.75 cm of wire in the field What is the average field strength (T)? Grade Summary Deductions Potential B 1.37 1% 99% 789 HOME Submissions Attempts remaining:9 1%per attempt) tan)T cosO cotanO)asin0 acosO sin0) A 456 - detailed view atan()acotanO 1% coshOtanh)cotanhO Degrees Radians END VOI BACKSPACE | DELI CLEAR Submit Hint I give up! Hints: 1% ded uction per hint. Hints remaining Feedback: 0% deduction per feedback.Explanation / Answer
We know that magnetic force is given by:
F = i*LXB
F = i*L*B*sin theta
Using given values:
i = 45 Amp
F = 2.14 N
L = 3.75 cm = 0.0375 m
theta = 90 deg
So,
B = F/(i*L*sin theta)
B = 2.14/(45*0.0375*sin 90 deg)
B = 1.27 T
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