Chapter 11, Problem 028 A 5.68 kg particle-like object moves in a plane with vel

Question

Chapter 11, Problem 028 A 5.68 kg particle-like object moves in a plane with velocity components v - 74.6 m/s and vy- 42.9 m/s as it passes through the point with (x, y) coordinates of (1.45 -8.48) m. Just then, in unit-vector notation, what is its angular momentum relative to (a) the origin and (b) the point (-6.63, -6.63) m? (a) Number (b) Number Click if you would like to Show Work for this question: Qpen Show Work k Units k Units SHOW HINT By accessing this Question Assistance, you will learn while you earn points based on the Point Potential Policy set by your instructor Question Attempts: 0 of 3 used SAVE FOR LATER SUBMI

Explanation / Answer

a)

relative to the origin

position vector is r = 1.45 i - 8.48 j

m = 5.68 kg

V = 74.6 m/s i + 42.9 m/s j

angular momentum is J = m*(r X v) = 5.68*(1.45 i - 8.48 j) X ( 74.6 i +42.9 j)

J = 5.68*(62.205 k + 632.608 k) = 3946.5 k hat kg m^2 s^-1

b) relative to the point (-6.63,-6.63)

position vector is r = (-6.63-1.45)i + (-6.63+8.48) j

r = -8.08 i + 1.85 j

J = m*(r X v) = 5.68*(-8.08 i + 1.85 j ) X ( 74.6 i + 42.9 j )

J = 5.68*(-346.63* k - 138.01 k ) = 2752.8 kg m^2 s^-1

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