Name April 2018 PHY 161 UNIVERSITY PHYSICS 11 QUIZ IV MULTIPLE CHOICE: Select th
ID: 2034427 • Letter: N
Question
Name April 2018 PHY 161 UNIVERSITY PHYSICS 11 QUIZ IV MULTIPLE CHOICE: Select the best answer 1. If 20 amperes circulate in a closed circuit, how much charge passes any point in 5 sec? 0.25 C c.20? d. 100 C 2. A metal wire has a resistance of 1.0-Ohm. What will be the resistance of a wire made of the same material but twice as long and with half the cross-sectional area? a 0.4-0hmb. 2.0-0hm c. 0.02-Ohmd. 4.0-0hm The rate at which energy is dissipated in a lamp that carries 0.5 A at 120 V is a. 1/6 watts 3. b. 2 watts ?. 60 watts d. 240 watts 4. A 12 Q load is connected across a 6.0 V source. How much energy does it use in % an hour? 1 kWh-3.6 X 10* J a. 1.5 X 103kWh b. 2.0 X 10 kWh d. 12.0 X 10 kWh c. 3.0 X 10kWh of the following, the copper conductor that has the least resistance is a. thin, long, and hot c. thick, long, and hot b. thick, short, and cool d. thin, short, and cool __ 6. If all the components of a circuit are connected in series, the physical quantity tht is the same at all points is the a. voltage b. current c. resistance d. power 7. The ratio of the potential difference across a conductor and the current in the of the conductor. conductor is called the d. resistance 8. Two lamps, one with a thick filament and one with a thin filament of the same length and material, are connected in series to a battery. The voltage is greater across the lamp with the a. thick filament b thin filamentc.voltage is the same for both 9. Which statement is correct? b. Voltage flows through a circuit. a. Charge flows in a circuit. c. Resistance is established across a circuit.d. Current causes voltage.Explanation / Answer
1) current = charge per unit time
I = q/t
20 = q / 5
q = 100 C
so option d) 100 C is the correct answer
2) R = pL/A
R1 = pL/A
R2 = p*2L/A/2 = 4pL/A
R2 / R1 = 4
R 2= 4R1
R2 = 4*1 = 4 ohm
3) P = VI = 0.5*120 = 60 W
4) P = V^2 / R
= 6^2 / 12 = 3 W
energy used for 1/2 hour = 3*30*60 = 5400 J
5400 / 3.6*10^6 = 1.5*10^-3 kWh
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