View History Bookmarks Window Help 66% Mon 7:07 PM ao E E.-I Chegg.com WileyPLUS

Question

View History Bookmarks Window Help 66% Mon 7:07 PM ao E E.-I Chegg.com WileyPLUS WileyPLUS: MywileyPLUSIHelp Contact Us I Log Out Halliday, Fundamentals of Physics, 10e Physics (1201/1202/2110/2112/2113) Gradebook ORION Downloadable eTextbook ent SCREENPRINTER VERSION BACK NEXT Question 1 Your answer is partially correct. Try again. particle undergoes a one-dimensional elastic collision with an initially stationary atom. What percentage of the subatomic particle's initial kinetic energy is transferred to kinetic energy of the atom? (The mass of the atom is 2350 times the mass of the subatomic particle.) percent the tolerance is +/-2% Question Attempts: 1 of 12 used SAVE FOR LATER SUBMIT ANSWER 2

Explanation / Answer

m1 = mass of subatomic particle = m

m2 = mass of atom = 2350 m

v1i = initial velocity of the subatomic particle

v2i = initial velocity of the atom = 0 m/s

v1f = Final velocity of the subatomic particle

v2f = Final velocity of the atom

using conservation of momentum

m1 v1i + m2 v2i = m1 v1f + m2 v2f

m v1i + (2350 m) (0) = m v1f + (2350 m) v2f

v1i = v1f + (2350 ) v2f

v1f = v1i - (2350 ) v2f eq-1

using conservation of kinetic energy

m1 v21i + m2 v22i = m1 v21f + m2 v22f

m v21i + (2350 m) (0)2 = m v21f + (2350 m) v22f

m v21i = m (v1i - (2350 ) v2f )2 + (2350 m) v22f

v21i = (v21i + (2350 )2 v22f - 4700 v1i v2f ) + (2350 ) v22f

(2350 )2 v22f - 4700 v1i v2f + (2350 ) v22f = 0

2350 - 2 (v1i /v2f ) + 1 = 0

v1i /v2f = 1175.5

v2f /v1i = 1/1175.5

Ratio of kinetic energies is given as

KEatom/KEpartcile = m2 v2f2/(m1 v1i2) = (m2/m1) (v2f /v1i )2 = (2350) (1/1175.5)2 = 0.0017

percentage

KEatom x 100/KEpartcile = 0.0017 x 100 = 0.17 %

Related Questions

Navigate

• Browse (All)
• Browse V
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.