Part A An electron moves in the magnetic field B- 0.410i T with a speed of 0.800

Question

Part A An electron moves in the magnetic field B- 0.410i T with a speed of 0.800 x10 m/s in the directions shown in the figure. For each, what is magnetic force F on the electron? (Figure 1) You may want to review (Pages 815-820) For help with math skills, you may want to review: Express vector F in the form of F, Fy F, where the x, y, and z components are separated by commas. View Available Hint(s) Submit Figure 1 of 1 Part B Express vector F in the form of F, Fy, F, where the x, y, and z components are separated by commas. View Available Hint(s) 45

Explanation / Answer

(A) F = q (v x B)

vector v = - vj

vector B = B i^

F = (-e)(-v j^ x B i^)

F = - e v B k^

F = - (1.6 x 10^-19 x 0.8 x 10^7 x 0.410 )

F = - 5.25 x 10^-13 N k^

Ans: 0, 0, - 5.25 x 10^-13

(B) vector v = - v cos45 j^ + v sin45 k^

F = (e v B cos45)(-k^) - (e v B sin45 ) j^

e v B sin45 = 3.71 x 10^-13 N  

Ans: 0, - 3.71 x 10^-13 , - 3.71 x 10^-13

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