A transformer has 15 turns of wire in its primary coil and 60 turns in its secon

Question

A transformer has 15 turns of wire in its primary coil and 60 turns in its secondary coil. An alternating voltage with an effective value of 110 V is applied to the primary coil. At the secondary coil, an alternating voltage with an effective value of 440 V is obtained. 14 A of current is supplied to the primary coil of the transformer. Calculate the maximum effective current in the secondary coil. Round the final answer to one decimal place. A transformer has 15 turns of wire in its primary coil and 60 turns in its secondary coil. An alternating voltage with an effective value of 110 V is applied to the primary coil. At the secondary coil, an alternating voltage with an effective value of 440 V is obtained. 14 A of current is supplied to the primary coil of the transformer. Calculate the maximum effective current in the secondary coil. Round the final answer to one decimal place.

Explanation / Answer

For transformers we know that

Np/Ns = Vp/Vs = is/ip

N = number of turns

V = Voltage

i = current

So,

is = ip*(Vp/Vs)

Using given values:

is = 14*(110/440) = 3.5 Amp

OR

is = ip*(Np/Ns)

is = 14*(15/60) = 3.5 Amp

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