12. + -/10 points SerPSE9 26.P.026.soln. Find the following. (In the figure, use

Question

12. + -/10 points SerPSE9 26.P.026.soln. Find the following. (In the figure, use C1-25.20 ?F and C2 19.20 ?F) 6.00 ?F 9.00 V (a) the equivalent capacitance of the capacitors in the figure above (b) the charge on each capacitor on the right 25.20-?F capacitor on the left 25.20-uF capacitor on the 19.20-uF capacitor on the 6.00-uF capacitor (c) the potential difference across each capacitor on the right 25.20-?F capacitor on the left 25.20-uF capacitor on the 19.20-uF capacitor on the 6.00-uF capacitor

Explanation / Answer

Remember:
For parallel combination
Ceq = C1 + C2 + C3 +...............
for series combination
1/Ceq = 1/C1 + 1/C2 + 1/C3 + ............
for 2 capacitors in series it will be
Ceq = C1*C2/(C1+C2)
Using this Information:

C2 and 6 uF are in parallel, So

Cp = C2 + 6 = 19.20 + 6.00 = 25.20 uF

Now Cp, C1 and C1 are in series, So

Ceq = (1/Cp + 1/C1 + 1/C1)^-1

Ceq = (1/25.20 + 1/25.20 + 1/25.20)^-1

Ceq = 25.20/3 = 8.40 uF

Now we know that

Qeq = Ceq*V

Qeq = 8.40*9.00 = 75.6 uC

Now remember in capacitors parallel combination voltage distribution in each part will be same and in series combination charge distribution in each capacitor will be same.

Charge on C1 (right) = Charge on C1 (left) = charge on Cp = 75.6 uC

Charge on C1 (right) = 75.6 uC

Charge on C1 (left) = 75.6 uC

Voltage on C1 (right) = Q1/C1 = 75.6/25.20 = 3.00 V

Voltage on C1 (left) = Q1/C1 = 75.6/25.20 = 3.00 V

Voltage on Cp = Qp/Cp = 75.6/25.20 = 3.00 V

Since C2 and 6.00 uF are in parallel, So

Voltage on C2 = Voltage on 6.00 uF = Vp

Voltage on C2 = 3.00 V

Charge on C2 = C2*V2 = 19.20*3 = 57.6 uC

Voltage on 6.00 uF = 3.00 V

Charge on 6.00 uF = C*V = 6*3 = 18.0 uC

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