(10%) Problem 3: Two blocks are joined by a massless string which passes through
ID: 2035624 • Letter: #
Question
(10%) Problem 3: Two blocks are joined by a massless string which passes through the center of a rotating turntable. The blocks have masses M1 - 18 kg and M2 2.3 kg. Block 1 rests a distance r 0.24 m from the center of the turntable. The coefficient of static friction between block and turntable is u,-0.51. Block 2 hangs vertically underneath. 4 Ctheexpertta.com At what velocity will the first block start to move outward in mis? Grade Summary Deductions Pinential 100% Late work % 100% Late Potential 100% sinO | cos() | tan() | ?|( 71819 cotan0 asin acosO atan acotan sinh0 coshO tanhO cotanh0+ Submissions 1 2 3 Attempts remaining: ( per attempt) detailed view O Degrees Radians Submit Hint I give up! Hints: deduction per hint. Hints remaining: Feedback: deduction per feedback.Explanation / Answer
According to the given problem,
There are three forces on Block 1. The weight of Block 2 and the friction force are preventing it from moving outward. The centripetal force is causing it to move outward. When the centripetal force is equal to the sum of the other two forces, Block 1 will start to move outward.
Weight = 2.3 * 9.81 = 22.563 N
Ff = 0.51 * 1.8 * 9.81 = 9.00558 N
Total = 22.563 + 9.00558 = 31.56858 N
Fc = 1.8 * v2/0.24
Using Newtons laws,
1.8 * v2/0.24 = 31.56858
v2 = 31.56858 * 0.24/1.8
v = ?(31.56858 * 0.24/1.8)
This is approximately 2.05 m/s.
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