10. + Question Details SerCP8 19-P030 My Notes Ask Your Teacher A copper wire is

Question

10. + Question Details SerCP8 19-P030 My Notes Ask Your Teacher A copper wire is 10.00 m long and has a cross-sectional area of 2.00 x 10-4 m2. This wire forms a one turn loop in the shape of a square and is then connected to a battery that applies a potential difference of 0.100 V. If the loop is placed in a uniform magnetic field of magnitude 0.300 T, what is the maximum torque that can act on it? The resistivity of copper is 1.7 × 10-8 ? nI. N·m Need Help? Read It Talk to a Tutor Show My Work (Optional) Submit Answer Save Progress Practice Another Version

Explanation / Answer

R = resistance = rho*L/A

resistivity rho = 1.7*10^-8 ohm m

L = length = 10 m

A = area of cross section = 2*10^-4 m^2

Resistance R = 1.7*10^-8*10/(2*10^-4) = 0.00085

I = current in wire = V/R

V = potential difference = 0.1 v

I = 0.1/0.00085 = 117.65 A

perimeter of square 4l = L

length of side l = L/4 = 10/4 = 2.5 m

torque = N*I*A*B*sintheta

N= number of loop = 1

A = area of loop = l^2

theta = angle between normal and magnetic field

for maximum torque theta = 90

maximum torque = N*I*A*B

maximum torque = 1*117.65*2.5^2*0.3 = 221 Nm

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