1. One of the plates of a parallel plate condenser is suspended from the beam of

Question

1. One of the plates of a parallel plate condenser is suspended from the beam of a balance. The separation between the plates is x-5 mm and the are area of the plates is A- 628 cm2. If a mass of M=0.04 gm has to be placed on the other pan of the balance to restore equilibrium. find the potential difference V between the capacitor plates 2. The outer one of two concentric metallic spheres having radii 4 cm and 6 cm has a charge of +30 microC. If the inner sphere is earth what is the charge on it? What is the capacitance of the system? 3. Find the electric field potential and strength at the center of the hemisphere of radius R charged uniformly with the surface density ?? 4. Two equal charges q are kept fixed at -a and a along X-axis. A particle of mass m and charge Q/2 is brought to the origin and given a small displacement. Describe the motion when the displacement is along (a) along X-axis (b) along Y-axis 5. A double-slit apparatus is immersed in a liquid of refractive index= 1.33. It has a slit separation of 1 mm and distance between the plane of slits and screen is 1.33m. The slits are illuminated by a parallel beam of light whose wavelength in vacuum is 6300A (a) Calculate the fringe width b) If one of the slits of the apparatus is covered by a thin glass of refractive index-1.53. Find the minmium thickness of the sheet to bring the adjacent minimum on the axis

Explanation / Answer

1)We know that

C = e0 A/d

C = 8.85 x 10^-12 x 0.0628 /5 x 10^-3 = 1.11 x 10^-10

We know that

U = 1/2 C V^2

PE = m g d

for equilibrium

U = PE

1/2 C V^2 = m g d

V = sqrt (2 m g d/C)

V = sqrt (2 x 0.04 x 10^-3 x 9.81 x 5 x 10^-3/1.11 x 10^-10) = 188.02 V

Hence, V = 188.02 Volts

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