Page 3 of 8 5. es slide a box of mass 200 kg, which was initially at rost byo ,
ID: 2036263 • Letter: P
Question
Page 3 of 8 5. es slide a box of mass 200 kg, which was initially at rost byo , -15 N along a frictionless orce F (b) a distance of 10 m ess toor. Employee-1 pushes the box with a constant forcs F,15 N directant with a con Employee-1 an angle 309 downward from the horizontal; and Employee-2 puile t lls the box 20 N directed at an angle 40° above the horizontal as showin (a) Calculate the net work done on the object by force F, and F durin n figure. What is the velocity of the object at the end of the displa cement 10 m,? Employee-2 Employee-1 FN F2 40° F1 Fo .YExplanation / Answer
work done = F*s*costheta
work done by force F1 , W1 = F1*d*cos30
work done by force F2 , W2 = F2*d*cos40
net work done , Wnet = W1 + W2 = F1*d*cos30 + F2*d*cos40
net work done = Wnet = (15*10*cos30) + (20*10*cos40) = 283.11 J
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part(b)
from work energy relation
net work done Wnet = change in KE
Wnet = (1/2)*M*(vf^2 - vi^2)
initial velocity = vi = 0
M = mass of box = 200 kg
283.11 = (1/2)*200*(vf^2-0)
vf = 1.683 m/s <<<<<--------ANSWER
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