(a) Calculate the intensity I 1 of the light after ithas passed through the firs

Question

(a) Calculate the intensity I1 of the light after ithas passed through the first polarizer. Express your answer as afraction of I0.

I1 / I0 =      

(b) The second polarizer is set at various angles within the rangeq 2 = 0 to 90°.Calculate the intensity of the light after it has passed through thesecond polarizer for the following values of q 2. Express each answer as a fractionof I1.

At q 2 = 0°:   I2 / I1 =    

At q 2 = 35°:   I2 / I1 =    

At q 2 = 90°:   I2 / I1 =

Explanation / Answer

a) I1 = IOcos2(theta)

I1 / IO = cos2(theta)

I1 / IO = cos2(19)

I1 / IO = 0.894

b) I2 = I1cos2(19°) cos2(90° - q2)

  I2 / I1 = cos2(19°) cos2(90° - q2)

Now, put different vlues of q2,

For q2 = 0 ,  I2 / I1 = cos2(19°) cos2(90° - 0)

I2 / I1 = 0

For q2 = 35 ,  I2 / I1 = cos2(19°) cos2(90° - 35)

I2 / I1 = 0.294

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