Please answer 52, 53, 57 52. A 34 ? and a 4S ? resistor are connected in series.

Question

Please answer 52, 53, 57

52. A 34 ? and a 4S ? resistor are connected in series. A) Find the equivalent resistance. B) Find the current through each resistor and the voltage across each resistor when this series combination is connected across a 7:5 V battery 53, A 250 ? resistor and a 370 O resistor are connected in parallel. A) Find the equivalent resistance. B) Find the current through each resistor and the voltage across each resistor when this series combination is connected across a 12 V battery 5 7, You're given a box of 10 ? resistors (unlimited supply). How would you connect the resistors to the following equivalent resistances: a) 20 b) 350 c) 7 ? d) 19

Explanation / Answer

Remember:
For series combination
Req = R1 + R2 + R3 +...............
for parallel combination
1/Req = 1/R1 + 1/R2 + 1/R3 + ............
for 2 resistors in parallel it will be
Req = R1*R2/(R1+R2)
Remember in resistors parallel combination voltage distribution in each part will be same and in series combination current distribution in each resistor will be same.
Using this Information:

52

Req = 34 + 45 = 79 ohm

ieq = V/Req = 7.5/79 = 0.095 Amp

Since in series So

Current in 34 ohm = current in 45 ohm = 0.095 Amp

Voltage in 34 ohm = 0.095*34 = 3.23 V

Voltage in 45 ohm = 0.095*45 = 4.27 V

53

Req = 250*370/(250 + 370) = 149.2 ohm

ieq = 12/149.2 = 0.080 Amp

Since in parallel So

Voltage in 250 ohm = Voltage in 370 ohm = 12 V

Current in 250 ohm = 12/250 = 0.048 Amp

Current in 370 ohm = 12/370 = 0.032 Amp

57.

For Req = 2 ohm

Req = R/n

n = R/Req = 10/2 = 5 ohm

Connect five 10-ohm resistor in parallel

for 35 ohm

Break 35 in (30 + 5)

for series, Req = n*R, then n = 30/10 = 3

for parallel, Req = R/n, then n = 10/5 = 2

So add two 10-ohm in parallel, then three 10 ohm in series with them

for Req = 7 ohm

Break into (5 + 2)

add five 10 ohms in parallel and then two 10 ohm in parallel, then connect both parallel circuit in series

for Req = 19 ohm

break it into (10 + 5 + 2 + 2)

(one 10 ohm) in series with (two 10 ohms in parallel) in series with (five 10 ohms in parallel) in series with (five 10 ohms in parallel).

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