need help with 6-9 QUESTION 5 When Lebron is at his highest (42 in-but in meters
ID: 2036574 • Letter: N
Question
need help with 6-9
QUESTION 5 When Lebron is at his highest (42 in-but in meters), what is his Potential Energy? (Hint: mgh) 1184.2 QUESTION 6 Using the Work Energy Theorem, with what velocity did he take off from the floor? (Hint 1/2mva2 mgh Looks like the masses cancell) QUESTION 7 If he was in contact with the floor for .05 s and his initial velocity was zero and his final velocity you computed in problem 5., with what force did he push off the floor? QUESTION 8 The instant Lebron's feet leave the floor, what is the magnitude of the acceleration acting on him? QUESTION 9 Knowing his initial velocity from Problem 6, let's think about how long he was in the air. His initial height is zero AND his final height is zero. Yeah! Thus the equation is 0 = 4.64 t-4.9 t' We know how to do thistor!! whoo-hoo!Explanation / Answer
6) 1/2*m*v2 = m*g*h
mass will cancel on both sides,
v2 = 2*m*g*h
v = ? 2mgh
7) Using v = u + at we can find the acceleration,
use the v (final velocity) from problem 5 , and set the u (initial velocity) = 0, t = 0.05 seconds
After calculating a, use F = ma to find the force
8) Already found in (7)
9) 4.64t - 4.9t2
4.64t = 4.9t2
4.64 = 4.9t
t = 4.64 / 4.9 = 0.94694 seconds.
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.