TFW 11:05 AM @ 69% LON-CAPA Satellite in orbit around Earth capa9.phy.ohio.edu T

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TFW 11:05 AM @ 69% LON-CAPA Satellite in orbit around Earth capa9.phy.ohio.edu TimerNotesEvaluate Feedback Print Info Satellite in orbit around Earth Due in 12 hours, 55 minutes Consider a satellite (mass 8.80 kg) in a circular orbit about Earth. Calculate the following properties of the satellite given a radius r of its orbit of 2.40x107 m. Its period Submit AnswerIncorrect. Tries 1/10 Previous Tries Its kinetic energy: Submit AnswerTries 0/10 Its angular momentum: Submit Answer Tries 0/10 Its speed Submit AnswerTries 0/10 Post Discussion Send Feedback

Explanation / Answer

Speed of the satellite is v = sqrt(G*M/r) = sqrt(6.67*10^-11*5.98*10^24/(2.4*10^7))

M is the mass of earth

v = 4076.7 m/s

Kinetic energy is KE = 0.5*m*v^2 = 0.5*8.8*4076.7^2 = 7.31*10^7 J

angular momentum is L =m*v*r = 8.8*4076.7*2.4*10^7 = 86100*10^7 kg m^2/s

speed is v = 4076.7 m/s

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