Forces on a strut Due in 12 hours, 57 minutes and e?-60.0 respectively as shown

Question

Forces on a strut Due in 12 hours, 57 minutes and e?-60.0 respectively as shown in the figure. The mass of the A 47.0 kg boy stands on the edge of a stnit hinged to the flonr and suspended by an inextensible cable. The cable and the st ut make ang es ?? 36 n strut is 16.0 kg. Hinge What Is the tenslon T In the cable? 230 3N Submit Answer Tries 2/10 Prevlous Tries What Is the horizontal component of the force on the hinge? Submit Answer Tries 0/10 What is the vertical camponent nf the force on thei? Submil ArisweTries f10 Post Discussion Send Feedba

Explanation / Answer

About hinge, the moment is zero. So, 16*9.81*l/2*cos60 + 47*9.81*l*cos60 = T*l*cos66 { where l is the length of strut, T is tension in cable and angle the cable makes with strut is 180-120-36= 24, so the angle it makes with normal to strut is 66 }

So, T = (39.24+230.535)/0.4067 = 663.27 N

Net force on strut is zero. So, horizontal component of force on the hinge is 663.27cos36 = 536.6 N

Similarly, vertical component of force on the hinge is (47+16)*9.81+663.27sin36 = 1007.9 N

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