chapter 24 part 1 1. The maximum magnetic field strength of an electromagnetic f

Question

chapter 24 part 1

1. The maximum magnetic field strength of an electromagnetic field is 445.8×106 T . Calculate the maximum electric field strength in kV/m if the wave is traveling in a medium in which the speed of the wave is 0.67c.

2. What is the intensity of an electromagnetic wave with a peak electric field strength of 140.8 V/m?

3. Electromagnetic radiation having a 23.6 m wavelength is classified as infrared radiation. What is its frequency in 1013Hz?

4. Find the intensity of an electromagnetic wave having a peak magnetic field strength of 6.73×109 T?  Give your answer in milliwatts per square meter.

Explanation / Answer

1.

Bmax = 445.8*10^-6 T

v = 0.67c

We know that

E/B = v

E = B*v

E = 445.8*10^-6*0.67*3*10^8 = 89605.8 V/m

E = 89.605 kV/m

2.

Intensity is given by:

I = e0*c*E0^2/2

Using given values

I = 8.85*10^-12*3*10^8*140.8^2/2

I = 26.32 W/m^2

3.

lambda = c/f

f = c/lambda = 3*10^8/(23.6*10^-6)

f = 1.27*10^13 Hz

4.

I = c*B0^2/(2*u0)

I = 3*10^8*(6.73*10^-9)^2/(2*4*pi*10^-7)

I = 5.41*10^-3 W/m^2

I = 5.41 mili-Watts/m^2

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