ProblemID-93713575 Multiple Choice Question 5.10 ?) 2of9 Part A A box with weigh

Question

ProblemID-93713575 Multiple Choice Question 5.10 ?) 2of9 Part A A box with weight 36 N present, denoted by n and t. A force diagram, showing the four forces that act on the box, is shown motion at constant velocity The box decelerates when force is on a rough horizontal surface An external force F is applied horizontally to the box. A normal force and a friction force are also in the figure When force F equals 4.7 N, the box is in F is removed. The magnitude of the acceleration of the box is closest to O 098 m/s 9 13 m/s 0 065 m/s zero 033 m/s2 Submit Request Answer

Explanation / Answer

Box is at constant velocity means acceleration is zero, which means

Net force = 0

Fnet = F - f = 0

F = f

F = uk*N

uk = F/N = 4.7/36 = 0.131 = coefficient of friction

Now when F is removed

Fnet = m*a = -f

a = -f/m = -uk*N/m

N = m*g

a = -uk*g

a = -0.131*9.81 = -1.285 m/sec^2

|a| = 1.285 m/sec^2 = 1.3 m/sec^2

Correct option is B.

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