Part A A Ferris wheel with a radius of 9.6 m rotates at a constant rate, complet

Question

Part A A Ferris wheel with a radius of 9.6 m rotates at a constant rate, completing one revolution every 34 s Find the magnitude of the passenger's acceleration at that time Express your answer using two significant figures. Suppose the Ferris wheel begins to decelerate at the rate of 0.20 rad/s when the passenger is at the top of the wheel. a 19 m/s Previous Answers Correct Part B Find the direction of the passenger's ac ation at that time. Elpress your answer using one decimal place o. 1606 below the direction of motion dis the b Submit Previous Answers Request Answer X incorrect; Try Again: 5 attempts remaining

Explanation / Answer

Centripetal acceleration

ac = w^2*r

w = 1 rev/34 sec = 2*pi/34 = 0.185 rad/sec

r = 9.6 m

ac = 0.185^2*9.6 = 0.328

tangential acceleration will be

at = alpha*r = 0.20*9.6 = 1.92 m/sec^2

a = ac i + at j

|a| = sqrt (0.328^2 + 1.92^2) = 1.94 m/sec^2

Part B

direction = arctan (0.328/1.92) = 9.69 deg below horizontal

You got phi = 0.1606 rad

you have to change it in unit of degree

1 rad = 57.296 deg

Please Upvote.

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