6.pdf- Adobe Acrobat Reader DC w Window Help ools PHYS 2 Hw#6.pdf 1 /9 ? 11796 Q

Question

6.pdf- Adobe Acrobat Reader DC w Window Help ools PHYS 2 Hw#6.pdf 1 /9 ? 11796 Question 2, chap 129, sect 3. part 1 of 2 10 points In the figure, a 30 cm length of conducting wire that is free to move is held in place between two thin conducting wires. All of the wires are in a magnetic field. When a 10 A current is in the wire, as shown in the figure, the wire segment moves upward at a constant velocity The acceleration of gravity is 9.81 m/s2 __ 30 cm 10 A 10 A 10 A a) Assuming the wire slides without frietion on the two vertical conduetors and has a mass of 0.12 kg, find the magnitude of the minimum magnetic field that is required to move the

Explanation / Answer

Wire is moving upward with a constant velocity, which means

acceleration = 0, So

Net Force = 0

Fg - Fm = 0

Fg = Fm

m*g = i*L*B

B = (m*g)/(i*L)

B = 0.12*9.81/(10*30*10^-2)

B = 0.392 T

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