thin, diverging lens having a focal length of magnitude 45.0 cm has the same pri
ID: 2037558 • Letter: T
Question
thin, diverging lens having a focal length of magnitude 45.0 cm has the same principal axis as a concave mirror with a radius of 60.0 cm. The center of the mirror is 20.0 cm from the lens, with the lens in front of the mirror. ?, object is placed 21.0 cm in front of the lens. 1) Where is the final image due to the lens-mirror combination Enter the image distance with respect to the mirror. Follow the sign convention. (Express your answer to three signiticant figures.) cm Submit You currently have 2 submissions for this question. Only 10 submission are allowed. You can make & mare submissions for this question. Your submissions: | 14.32 Computed value: 14.32 Feedback: X Submitted: Sunday, April 8 at 1:37 PMExplanation / Answer
1)
f1 = -45 cm
u1 = 21 cm
let v1 is the image distance from lens
use, 1/v1 + 1/u1 = 1/f1
1/v1 = 1/f1 - 1/u1
1/v1 = 1/(-45) - 1/21
v1 = -14.3 cm
this image acts as object for the concave mirror
object distance, u2 = -(14.3 + 20)
= -34.3 cm
f2 = R/2 = 60/2 = 30 cm
let u2 is the final image distance from the mirror.
use, 1/v2 + 1/u2 = 1/f2
1/v2 = 1/f2 - 1/u2
1/v2 = 1/30 - 1/(-34.3)
v2 = 16.0 cm <<<<<<<---------------Answer
4)
f2 = -R/2 = -60/2 = -30 cm
let u2 is the final image distance from the mirror.
use, 1/v2 + 1/u2 = 1/f2
1/v2 = 1/f2 - 1/u2
1/v2 = 1/(-30) - 1/(-34.3)
v2 = -239.3 cm <<<<<<<---------------Answer
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