Chapter 12, Problem 039 For the stepladder shown in the figure, sides AC and CE

Question

Chapter 12, Problem 039 For the stepladder shown in the figure, sides AC and CE are each 2.86 m long and hinged at C. Bar BD is a tie-rod 0.783 m long, halfway up. A man weighing 923 N climbs 2.15 m along the ladder. Assuming that the floor s frictionless and neglecting the mass of the ladder, find (a) the tension in the tie-rod and the magnitudes of the forces on the ladder from the floor (b) A and (c) E. (Hint: Isolate parts of the ladder in applying the equilibrium conditions.) (a) Number (b) Number (c) Number Units Units Units Click if you would like to Show Work for this question: Qpen Show Work acvPolicy I ?2000-2018JohnWilevasors..inc. All Rights Reserved. A Division of 20hr Alex asons-tne Version 4.24.5

Explanation / Answer

Angle CAE = Angle CBD =cos^-1(0.5*0.783/ 0.5*2.86) = 74.11 degrees and AE = BD*CA/CB = 1.566m

About A, net moment is zero. So, 2.15cos74.11 * 923 = Re * 1.566

So, reaction at E = 346.95 N

Ra + Re = 923N.

So, Ra = reaction at A = 576 N

About C, net moment on CE = 0 = Re* CE cos74.11 = T* CD sin74.11

So, tension in the tie-rod T = 197.53N

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.