To monitor the breathing of a hospital patient, a thin belt is girded around the

Question

To monitor the breathing of a hospital patient, a thin belt is girded around the patient's chest as in the figure below. The belt is a 190-turn coil. When the patient inhales, the area encircled by the coil increases by 45.0 cm2. The magnitude of Earth's magnetic field is 50.o HT and makes an angle of 25.5° with the plane of the coil. Assuming a patient takes 2.10 s to inhale, find the magnitude of the average induced emf in the coil during that time Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four-digit accuracy to minimize roundoff error. uV Coil Need Help?ReadIt Submit Answer Save Progress Practice Another Version

Explanation / Answer

emf= -N (d/dt)(BAcos(phi))

N=turns the coil makes

B=electric Field

A=area

Everything is constant except "A" so our "emf" equation becomes;

emf = - N(dA/dt)BCos(phi)

N = 190

dA/dt = .0045/2.1 m^2/s

B = 50x10^-6 T

phi = 90 – 25.5 = 64.5 deg (angle in formula is w.r.t to surface "normal", not surface plane)

Just plug & chug, we get:

|emf| = 8.76 x 10-6 V

= 8.76 uV

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.