Help Sb. Homework 3 Begin Date: 4/2/2018 12:01:00 AM-Due Date: 4/82018 11:39.00
ID: 2037873 • Letter: H
Question
Help Sb. Homework 3 Begin Date: 4/2/2018 12:01:00 AM-Due Date: 4/82018 11:39.00 PM End Date:4/13/2018 12:0000 AMM (14%) Problem 7: A solenood is created by wrapping a L-55 m log wue arond abollow tube ofdiameter D-35an. The wire diameter is d-Imm. The solenoid wire is then connected to a power supply so that a current of I- 7.5 A flows through the wire Randomized Variables L- 55 m D 3.5 cm d-I nom 17.5 A ??20% Part (a) White un expression for the mun ber oft umsN,In the solen oid. You do not nood to take into acount the diameter ofthe wre in this calculation A 20% Part (b) Calculate the number ofturns, N in the solenoid. N- Poteatial Amempes remaining 1 2le per amemp cotanasinacos0 atan0 acotan sinbO cosh tan cotanb 8 Degrees Hists:t dndacticn per hist HKats remaining - 20% Part (c) Write an expressaon for the length of the sole oid g) in terms of the diameter of the hollow tube D, the length of the wrel and the diameter of the wire d. Assume it is comstructed by using only 1 layer of loops (note that most solenoids are actually constructed with many layers, to maximize the magnetic field density). 20% Part (d) Calculate the length of the solenoid (L2) in meters. ii ? 20% Part (e) Calculate the magnitude of the magnetic feld at the center of the solenoid-teslaExplanation / Answer
PLEASE NOTE THAT I HAVE NOT PUT THE VALUE OF PI. IF YOU WNAT, YOU CAN PUT VALUE OF PI AS 22/7 OR 3.14 AND CHANGE THE EQUATION ACCORDINGLY
a) We know that length of wire wrapped around the solenoid is given as
L = N * pi*D
where pi*D is the circumference of solenoid, N - no. of turns
N = L / pi*D
b) N = 55 / pi*0.035
N = 500.20
so, number of turns = 500 turns
c) Number of turns per meter, n = 1000 / m
N = n*L2 where L2 is length of solenoid
L2 = N/n
L2 = L / pi*D / n
L2 = L*d / pi*D
d) L2 = N/n
L2 = 500 / 1000
L2 = 0.5 m
e) B = uo*n*I
where n = number of turns per meter = 1000 , uo = 4*pi*10-7
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