HW 95: RC Circuits Begin Date: PM End Date: (50%) Problem 1: A capacitor of capa
ID: 2037929 • Letter: H
Question
HW 95: RC Circuits Begin Date: PM End Date: (50%) Problem 1: A capacitor of capacitance C-95 F is initially uncharged. It is connected in series with a switch of negligible resistance, a resistor of resistance R 11.5 k2, and a battery which provides a potential difference of VB 170 v tus Otheex 17% Part (a) Calculate the time constant for the circuit in seconds. 17% Part (b) After a very long time after the switch has been closed, what is the voltage drop VC across the capacitor in t tus tial e = 1701 7 89 HOME Sub END | VOI BACKSPACE ?DEt| CLEAR Va Submit Hint I give up deduction per feedback. Hints: deduction per hint. Hints remaining:- Feedback: 17% Part (c) Calculate the charge Q on the capacitor a very long time after the switch has been closed in C. 17% Part (d) Calculate the current I a very long time after the switch has been closed in A. 6 17% Part (e) Calculate the time , after which the current through the resistor is one-third of its maximum value in s. ? 17% Part (f) Calculate the charge Q on the capacitor when the current in the resistor equals one third its maximum, value i = All content 2018 pet TA.LLCExplanation / Answer
a)
Time Constant
T=RC=(11.5*103)(9.5*10-6)
T=0.10925 s
b)
VC=170 V
c)
Q=CV =170*(9.5*10-6) =1.615*10-3 C
d)
Io=V/R =170/11500 =0.01478 A
e)
In a RC circuit current as a function of time is given by
I=Ioe-t/T
=>1/3 =e-t/0.10925
Ln(1/3) =-t/0.10925
t=0.12 s
f)
Q=Qo(1-e-t/T)
Q=(1.615*10-3))1-e-0.12/0.10925)
Q=5.3833*10-4C
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