Need help with part c in finding I2 4. 7/8 points I Previous Answers OSUniPhys1

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Need help with part c in finding I2

4. 7/8 points I Previous Answers OSUniPhys1 31.4.P059 My Notes Ask Your Teacher For the circuit shown below, ?-60 V, R1-28 ?, R2-56 ?, R3-84 ?, and L-3.0 mH. Find the values of 11 and 12 (in A) at the following times. (Indicate the direction with the signs of your answers.) R. (a) immediately after switch S is closed I0.714 12 = 0.714 (b) a long time after S is closed 11 = 0.974 20.584 (c) immediately after S is reopened (Assume the circuit has reached a steady state before S is reopened.) 120.389 (d) a long time after S is reopened

Explanation / Answer

Immediately after switch is opened, current through inductor does not change, ( as it does not change suddenly). Current through inductor long time after switch is closed or just before switch is opened is
I1 - I2 = 0.974 - 0.584 = 0.39 (values taken from part b)

This current runs through inductor after switch is opened, but completes loop, going through R2, in upward direction as current through inductor is in downward drection.
So I2 immediately switched is opened is -0.39 A ( i2 is shown downward)

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