#7 help please wag Ch 11, Magnetic s ike l x G A besm of al X Step-by Sterp ? No

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#7 help please

wag Ch 11, Magnetic s ike l x G A besm of al X Step-by Sterp ? Not secure www.weba signet webstudent Assignment Responses/subitdep-184 9713 Apps D Index of /Users/ » YouTube R Yahoo w Transfer Credit macomb m symbolab N Netfice Cokaler direct, w logn-WSU 1 283 WA 013 A beam of alpha particles is fired horizontally with a speed of 3.7 x 10 mis into a reoian where there is a vertical magnetic field of magnitude o 126 T. An alpha p neutrons, and has a mass of 6.64 x 1027 kg cleus of a hefum atom and as such, consists of two protons, two (a) Determine the length of time it will take an alpha partide to move halfway around a complete circle How are the speed, tme of travel, and distance traveled related, for the case of sn alpha partide traveling in a dircular path? What torce provides the centripetal force causing the alpha partide to travel in a dircular path? s ) Does the time found in part (a) increase, decrease, or stav the same, if the speed of the alpha partide is troled? increase o decrease o stay the same (c) Repeat part (a) for alpha partides with a speed of x10 m's. Additional Materials u eBopk Somit Ansner Save Progress Practca Anohenersion My Notes As direction of the magnetic force on the cuent n each of th e six cases la By

Explanation / Answer

r= mv/qB

where m = mass of alpha aprticle = 6.695*10^-27 kg

q = charge of alpha aprticle = 3.2*10^-19C

so, r= 3.7*10^5*6.695*10^-27 / 3.2*10^-19*0.126 = 0.0614m

time taken to cover half circle = pi*r/v = 3.14*0.0614/3.7*10^5 = 5.2*10^-7 s

Now it is said that the speed of alpha aprticle is tripled, then r becomes tripled. So, time taken to cover half circle = 3*pi*r / 3*v = pi*r/v. So, time period stays the same.

Now it is said that v= 1.1*10^5m/s ; r = 1.1*10^5*6.695*10^-27 / 3.2*10^-19*0.126 = 0.01825m

So, time taken = 3.14*0.01825 / 1.1*10^5= 5.2*10^-7 s

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