#3-An amusement park ride has people stand inside a 50-m-diameter hollow steel c
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#3-An amusement park ride has people stand inside a 50-m-diameter hollow steel cylinder with their backs against the wall. The cylinder spins up while the floor drops away. If all goes well, the passengers will stick to the wall and not slide down. Clothing has a static coefficient of friction in the range 0.60 to 1.0. What is the minimum angular speed, in rpm, for which the ride is safe? #4-In an amusement park ride called The Roundup, passengers stand inside a 18.0 m-diameter rotating ring. After the ring has acquired sufficient speed, it tilts into a vertical plane, as shown in the figure. Suppose the ring rotates once every 4.70 s. If a rider's eA Rotation axis mass is 53.0 kg... 0 a. How.much force does the ring push on her at the top of the ride? How much force does the ring push on her at the bottom of the ride? What is the longest rotation period of the wheel that will prevent the riders from falling off at the top? b. c.Explanation / Answer
3)
fS = us*mrwmin2
where fS = static force,
equating this force to the weight of an individual
us*mrwmin2 = mg
m will cancel out, we will have
us*r*wmin2 = g
wmin = sqrt ( g / us*r)
wmin = sqrt ( 9.8 / 0.6*2.5)
wmin = 2.556 rad/s
In rpm, wmin = 2.556*60/2*pi
wmin = 24.4
as rpm cannot be in decimals,
so, wmin = 24 rpm
4 ) F = m*2*pi*f*r
F = 53*2*pi*1/4.7*9
F = 637.68 N
at top , N = 637.68 - 53*9.8 = 118.28 N
at bottom, N = 637.68 + 53*9.8 = 1157.1 N
mw^2R = mg
w = 1.0435 rad/s
T = 2*pi / w
T = 6.0212 SECONDS
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