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LENZ\' LAW EM Hw-115 I. The diagram at right shows a copper wire loop held in pl

ID: 2038561 • Letter: L

Question

LENZ' LAW EM Hw-115 I. The diagram at right shows a copper wire loop held in place near a solenold. The switch in circuit containing the solenoid is initially open. a. Use Leaz law to predict whether current will flow through the Wire WireSolenoid wire of the loop in each of the following cases. Explain your loogp reasoning . just after the switch has been closed e a long time after the switch has been closed just after the switch has been reopened . a long time after the switch has been reopened b. For each of the cases in which you predicted that there will be an induced current, draw a diagram that illustrates: . the direction of the current through the wire of the loop, the direction of the magnetic moment of the loop, and the direction of the magnetic force exerted on the loop. is the force on the wire loop in a direction that would tend to increase or decrease the change in net flux through the wire loop? CPearson

Explanation / Answer

1

a)

just after the switch is closed , the current increases in the solenoid upto the steady value. hence the magnetic field by the solenoid going through the loop increase. since the due to increase in magnetic field through the loop , the magnetic flux through the loop increase , the loop induce current in it to oppose the increase.

hence the current flows

a long time after switch has been closed , the current in the solenoid is constant and produce constant magnetic field through the loop. since the magnetic field through the loop does not change and hence the magnetic flux of loop remain constant. so it does not induce any current in itself.

so loop induce no current.

Just after the switch has been reopened, the current decrease in the solenoid from steady value to zero. hence the magnetic field by the solenoid going through the loop decrease. since the due to decrease in magnetic field through the loop , the magnetic flux through the loop decrease , the loop induce current in it to oppose the decrease..

hence the current flows

a long time after switch has been reopened , the current in the solenoid is zero and produce zero magnetic field through the loop. since the magnetic field through the loop is zero. so it does not induce any current in itself.

so loop induce no current.