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P.S.: I need an answer for the second question. The answer for the second questi

ID: 2038927 • Letter: P

Question

P.S.: I need an answer for the second question. The answer for the second question IS NOT 2.43*10^(-4) J!!

RC Circuit- Energy The following equations describe the charge and current in an RC circuit with a battery Qtt)- C(1 ell-R )l) ? 1(t) .el(-t)/(R-C)] DATA: emf 9.00 V, C = 6.00 ?F, and R = 3.00 ?. From these equations, calculate the total energy dissipated as Joule heat in the resistor in the time interval between t = 0 s and t = infinity What is the total energy that the battery must deliver in this time interval?

Explanation / Answer

energy delivered by battery=integration of V(t)*I(t)*dt

=integration of E*(E/R)*exp(-t/(R*C))*dt

=(E^2/R)*R*C*(-exp(-t/(R*C))

using limits from t=0 to t=infinity,

energy delivered=E^2*C(1-0)

=9^2*6*10^(-6)

=4.86*10^(-4) J