The current in an RI circuit builds up to two-third of its steady-state (maximum

Question

The current in an RI circuit builds up to two-third of its steady-state (maximum) v 4.00 s. Find the inductive time constant. 3. value in A circular conducting loop lies flat on a table next to a very long straight wire, as shown below. The current in the wire flow to the right and is increasing.with time. What w the direction of the induced current in the loop (clockwiss or counterclockwise)l (Hint: Start by showing the B-field produced by the wire inside the loop using crosses or dots.) 4. ould be In each of the two separate situations (a) and (b) below there is bar magnet in the vicinity of a solenoid which is attached to a galvanometer G. Indicate the direction of the deflection of the galvanometer's needle (left or right) while the magnet is moving in the direction shown. (Use Lenz's law to explain!) 5.

Explanation / Answer

3)Given,

I = 2/3I0 ; t = 4 s

We know that

I = I0 (1 - e^-t/Tau)

Where Tau is the inductive time constant

2/3 I0 = I0 (1 - e^-t/tau)

0.67 = (1 - e^-t/tau)

e^-t/tau = 1 - 0.67 = 0.33

taking natural long both sides

-t/tau = -1.11

tau = t/1.11 = 4/1.108 = 3.61 s

Hence, tau = 3.61 s

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