interactive Solution 9.2 offers help in modeling this problem. The wheel of a ca

Question

interactive Solution 9.2 offers help in modeling this problem. The wheel of a car has a radius of o.375 m. The engine of the car applies a toeque of 312 N m to this wheel, which does not slip against the road surface. Since the wheel does not slp, the road must be applying a force of static frection to the wheel that produces a countertorque. Moreover, the car has a constant countertorque balances the applied torque. What is the magnitude of the static frictional force? velocity, so this Additional Materials section 91 Subn Answer Save Progress Pracice Another version

Explanation / Answer

Data:
?=312 N-m; r:=0.375 m;

Forces acting on the wheel (forget about those in the vertical direction):
Axle reaction force, A (reverse)
Traction force, F (forward)

Engine torque is ?, acting to the left of the car.

Torque due to F about the axle must therefore point right.

Torque balance:
r*F = ?

F = ?/r

F = 312/0.375

F=832 Newtons

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