The radius of curvature of a spherical convex mirror is 22 cm. Describe the imag
ID: 2039386 • Letter: T
Question
The radius of curvature of a spherical convex mirror is 22 cm. Describe the image formed when a 15-om-tall object is positioned at various distances. For each case, provide the image distance, the image height, the type of image (real or virtual), and the orientation of the image (upright or inverted) (a) 20 cm from the mirror d 24.4 x cm e real virtual Orientation of the image: upright s inverted (b) 22 cm from the mirror di 11 e real o virtual Orientation of the image: o upright s inverted (e) 100 em from the mirror di 165 hl = 12.35 rcal o virtual Orientation of the image o upright invertedExplanation / Answer
a)
f = focal length = - 22 cm
ho = object height = 15 cm
hi = image height = ?
do = object distance = 20 cm
di = image distance = ?
using the mirror equation
1/di + 1/do = 1/f
1/di + 1/20 = 1/(-22)
di = - 10.5 cm
using the equation
hi/ho = - di/do
hi/15 = - (- 10.5)/20
hi = 7.875 cm
Imgae distance : 10.5 cm
Image height : 7.875 cm
Type of image : Virtual
Orientation : Upright
b)
f = focal length = - 22 cm
ho = object height = 15 cm
hi = image height = ?
do = object distance = 22 cm
di = image distance = ?
using the mirror equation
1/di + 1/do = 1/f
1/di + 1/22 = 1/(-22)
di = - 11 cm
using the equation
hi/ho = - di/do
hi/15 = - (- 11)/22
hi = 7.5 cm
Imgae distance : 11 cm
Image height : 7.5 cm
Type of image : Virtual
Orientation : Upright
c)
f = focal length = - 22 cm
ho = object height = 15 cm
hi = image height = ?
do = object distance = 100 cm
di = image distance = ?
using the mirror equation
1/di + 1/do = 1/f
1/di + 1/100 = 1/(-22)
di = - 18.03 cm
using the equation
hi/ho = - di/do
hi/15 = - (- 18.03)/22
hi = 12.3 cm
Imgae distance : 18.03 cm
Image height : 12.3 cm
Type of image : Virtual
Orientation : Upright
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.