Two populations of mountain lions, each in Hardy-Weinberg equilibrium, were sepa

Question

Two populations of mountain lions, each in Hardy-Weinberg equilibrium, were separated by a river. The population on the west side of the river was too large to count and the population on the east side of the river had 100 individuals. In each population there were individuals with tufted tails, a phenotypic trait which was controlled by a recessive allele, t. The frequency of tufted tails among the population on the west side of the river was 0.49. The frequency of tufted tails among the population on the east side of the river was 0.25. During a drought, the river dried up and individuals from the west population moved east, where prey were more abundant, for two generation. In the first generation, half of the new population was migrants. In the second generation, 25% of the population was migrants. Migration stopped and the population reached Hardy-Weinberg equilibrium. What was the resulting frequency of tufted tails in the east population?

Explanation / Answer

According to hardy Weinberg principle,total genetic and allelic frequency remain constant in a population .

P + Q =1 where P is genotypic frequency of allele AA and Q is genotypic frequency for allele aa.

In the given situation ,the tufted tail(phenotypic trait) is controlled by a recessive allele aa.After migration from west to east,there is prey population in eastward direction and after generation reaches the hardy Weinberg law. It means that the genotypic frequency again becomes equal to the 0.25 after the migration from west to the east of river, as total genotypic frequency remains constant from generation to generation in a population.

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