The question is labeled M.3 At time t 0, a constant applied force, FA= 5N Iin th

Question

The question is labeled M.3

At time t 0, a constant applied force, FA= 5N Iin the positive a-direction, be n the block. At time t = 4 s, the force suddenly ceases to act (a) Compute the impulse provided to the block by the applied force while it acted, and explain (briefly) why this is the net impulse received by the block. (b) (i) Compute the initial momentum of the block, i.e., at t (ii) momentum and 0, Determine the (iii) velocity of the block at t = 4 s. M.3 A block of mass M 2kg is at rest at the origin of a horizontal frictionless plan At time t 0, a constant applied force, FA 4N [in the negative r-direction], begins to act 2 s, the force suddenly ceases to act. 0, a constant applied force, E th egative a-direction), act on the block. At time t (a) Compute the impulse provided to the block by the applied force while it acted, and explain (briefly) why this is the net impulse received by the block. (b) (i) Compute the initial momentum of the block, i.e., at t0. Determine the (ii) momentum and (iii) velocity of the block at t = 2 s. M.4 A football (soccer) player intends to redirect a 425 g ball, using her head. Th initial velocity of the ba is (8, 6) m/s in the plane containing both the incoming and outgoi inal ralocity is (8, -6)m

Explanation / Answer

M3. M = 2 kg, FA = 4 N , u =0, , t1 =0, t2 = 2s
impulse = change in momentum
from Newtons second law F = DP/DT
F = impulse/(t2-t1)
4 = impulse/(2-0)
impulse = 8 N
from conservation of momentum , intial momentum of system equal to final momentum of system, so the net force is converted nto net impulse received by block.

(b) pi = M*u
pi = 0

(ii) impulse = pf -pi

Pf = 8 kg.m/s

pf = Mvf
8 = 2*vf
vf = 4 m/s

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