help? 1. Calculate the tension in the crossbar. The ladder is uniform and has ma
ID: 2039961 • Letter: H
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help?
1. Calculate the tension in the crossbar. The ladder is uniform and has mass 40.0kg. 2. Find the speed at the bottom of the ramp of a hollow 4.00-kg, radius 0.200-m ball i it rolls and starts from rest at a point 5.00 m high. Assume no air drag 3. Find the mass of the pulley if the acceleration of the blocks is 0.500g. Mass-1 11.00kg. mass-2-44.00 kg and the pulley is a solid cylinder. The rope has a negligible mass and different tensions on both sides. 4. A horizontal spring (k-3.00 N/m) is compressed 0.500 m. Find the maximum speed a 5.00-kg mass connected to the spring has after it is released. Assume no friction. 5. Copper ( Y = 1.1 x 1011 Pa) and brass (Ys 9.0 x 1010 Pa) cylinders are stacked end to end. Each has a radius of 0.300 cm, the copper is 4.00 long and the brass 5.00 m long. If the compression force is 7550 N, what is the overall change in length M:? 900 1 0.300cmExplanation / Answer
1) If we draw a free body diagram, we see that
in y direction, W = FN
so, FN = W = mg
FN = 20*9.8 = 196 ( considering only left side)
Now, summing up the torques, we get
-T*2*sin 75 - W*2.5*cos 75 + R*5*sin 75 = 0
Putting R = T
-T*2*sin 75 - W*2.5*cos 75 + T*5*sin 75 = 0
T*3*sin 75 = 196*2.5*cos 75
T = 126.82 / 2.8978
T = 43.76 N
2) Moment of inertia of a hollow sphere., I = 2mr2 / 3
Conservation of energy gives
mgh = 1/2mv2 + 1.2Iw2
mgh = 1/2mv2 + 1/2*2mr2 / 3 * (v2 / r2 )
mgh = 1/2mv2 + 1/3mv2
m will cancel, we get
gh = 5/6v2
v = 7.668 m/s
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