Qn:3 poed olech Sutaue QUESTION 3 The heater element of an electric kettle has a
ID: 2040042 • Letter: Q
Question
Qn:3
Explanation / Answer
Given,
R = 150 Ohm ; V = 240 V
3.1)T1 = 15 deg ; T2 = 90 deg
eta = 80 %
We know that, P = I^2 R = V^2/R
P = 240^2/150 = 384 W
We know that,
Qw = 1 x 95 - 15 = 75 kcal
Wk = 0.15 x 90-15 = 11.25 kca;
Qtot = 75 + 11.25 = 86.25 kcal
we have eta = 80% = 0.8
Q(tot) = 0.8 x 384 x t/4200 = 0.073 t
t = 86.25/0.073 = 1180 s
Hence, t = 1180 s = 19.65 min
In this case, t = 75/0.073 = 1027.4 s
Hence, t = 1027.4 s = 17.12 min
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