(590) Problem 21: The 695-kg swimmer in the figure starts a race with an initial

Question

(590) Problem 21: The 695-kg swimmer in the figure starts a race with an initial velocity of 1.3 m/s and exerts an average force of 79 N backward with his arms during each 1.80 m long stroke 1.8 m Otheexpertta.com > 50% Part (a) what is his initial acceleration, in meters per square second, if water resistance is 46.5 N? Grade Summa Deductions Potential ry 096 100% 7 8 9 tanO ( acosO cosO Submissions Attempts remaining: !8 (290 per attempt) detailed view Sin cotan0asin0 atan acotan sinhO cosh0 anh cotanhO END Degrees Radians N0 CLEAR Submit Hint I give up! Hints: 1% deduction per hint. Hints remaining: 1 Feedback: 1% deduction per feedback. 50% Part (b) What is the subsequent average resistance force, in newtons, from the water during the 5.1 s it takes him to reach his top velocity of 2.3 m/s?

Explanation / Answer

here ,

part A) let the average acceleration is a

Using second law of motion

79 - 46.5 = 69.5 * a

a = 0.47 m/s^2

the acceleration is 0.47 m/s^2

part B)

let the average force is F

79 - F = 69.5 * (2.3)/5.1

solving for F

F = 47.7 N

the average resistance force is 47.7 N

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