1) A block of mass mi 10.5 kg slides along a horizontal surface with a kinetic f

Question

1) A block of mass mi 10.5 kg slides along a horizontal surface with a kinetic friction coefficient of 0.21 for a distance of 2.05 m before striking a stationary block of mass m2 5.25 kg. The first block has an initial velocity of v-6.25 m/s. a) Determine the acceleration of block 1 as its sliding before impact. b) Determine the velocity of block 1 just before it collides with block 2. c) Assuming that block one stops after it collides with block 2, what is block 2's velocity after impact? d) If the kinetic friction coefficient is 0.21 for block 2, determine how long block 2 slides before coming to a stop m2 Otheexpertta.com 0.25 ms

Explanation / Answer

1. given

m1 = 10.5 kg

uk = 0.21

d = 2.05 m

m2 = 5.25 kg

vi = 6.25 m/s

a. a1 = -uk*g = -2.0601 m/s/s

b. let final speed before collision = vf

then

2*a*d = vf^2 - vi^2

vf = 5.53318 m/s

c. assuming bock 1 stops after collision

hence speed of block 2 after collsiion = u

from conservation of momentum

m1*vf = m2*u

u = 11.066361642 m/s

d. uk = 0.21

distance travelled before coming to stop = l

2*a*l = -u^2

hence

l = 29.722916363 m

a = uk*g

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