Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

please write out answers (16 pts) Instructions: You MUST answer question number

ID: 2040285 • Letter: P

Question

please write out answers



(16 pts) Instructions: You MUST answer question number one. in oddition select either t mandatory). OR tinee G oe so Extro credit: Complete both questions 2 AND 3 1. (10 pts) Use the circuit diagram to answer the questions below R1 50 0 R2 70? a) (2 pts) What is the total resistance of the cecur? b) (1 pt) What is the current through the bamery c) (3 pts) What is the current through each r d) (3 pts) What is the potential difference fvtage across each resisto? e) (1 pt) Which resistor has the greatest electie power? R3 100 Q 12 V

Explanation / Answer

Remember:
For series combination
Req = R1 + R2 + R3 +...............
for parallel combination
1/Req = 1/R1 + 1/R2 + 1/R3 + ............
for 2 resistors in parallel it will be
Req = R1*R2/(R1+R2)
Using this Information:

R1 and R2 are in series, So

R12 = 50 + 70 = 120 Ohm

R12 and R3 are in parallel, So

Req = 120*100/(120 + 100) = 54.55 Ohm

Part B

From Ohm's law:

Ieq = V/Req = 12/54.55 = 0.22 Amp

Part C and D

Now remember in resistors parallel combination voltage distribution in each part will be same and in series combination current distribution in each resistor will be same. So

Voltage in R3 = Voltage in R12 = Voltage in Battery

Voltage in R3 = 12 V

Current in R3 = i3 = V3/R3 = 12/100 = 0.12 Amp

Current in R12 = 0.22 - 0.12 = 0.10 Amp

Since R1 and R2 are in series,
Current in R1 = Current in R2 = i12

i1 = 0.10 Amp

V1 = i1*R1 = 0.1*50 = 5 V

i2 = 0.10 Amp

V2 = i2*R2 = 0.1*70 = 7 V

Part E.

P1 = V1*i1 = 5*0.1 = 0.5 W

P2 = V2*i2 = 7*0.1 = 0.7 W

P3 = V1^2/R = 12^2/100 = 1.44 W

Resistor R3 have greatest power.

Please Uvpote.