please write out answers (16 pts) Instructions: You MUST answer question number
ID: 2040285 • Letter: P
Question
please write out answers
Explanation / Answer
Remember:
For series combination
Req = R1 + R2 + R3 +...............
for parallel combination
1/Req = 1/R1 + 1/R2 + 1/R3 + ............
for 2 resistors in parallel it will be
Req = R1*R2/(R1+R2)
Using this Information:
R1 and R2 are in series, So
R12 = 50 + 70 = 120 Ohm
R12 and R3 are in parallel, So
Req = 120*100/(120 + 100) = 54.55 Ohm
Part B
From Ohm's law:
Ieq = V/Req = 12/54.55 = 0.22 Amp
Part C and D
Now remember in resistors parallel combination voltage distribution in each part will be same and in series combination current distribution in each resistor will be same. So
Voltage in R3 = Voltage in R12 = Voltage in Battery
Voltage in R3 = 12 V
Current in R3 = i3 = V3/R3 = 12/100 = 0.12 Amp
Current in R12 = 0.22 - 0.12 = 0.10 Amp
Since R1 and R2 are in series,
Current in R1 = Current in R2 = i12
i1 = 0.10 Amp
V1 = i1*R1 = 0.1*50 = 5 V
i2 = 0.10 Amp
V2 = i2*R2 = 0.1*70 = 7 V
Part E.
P1 = V1*i1 = 5*0.1 = 0.5 W
P2 = V2*i2 = 7*0.1 = 0.7 W
P3 = V1^2/R = 12^2/100 = 1.44 W
Resistor R3 have greatest power.
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