3. A student was performing a double-slit experiment with two different colors.

Question

3. A student was performing a double-slit experiment with two different colors. He noticed that the 2 order bright fringe using 680-nm red light was in the same position as the 3d order bright fringe of the other color. What is the wavelength of this second light? Look up what color this wavelength corre sponds to. Setup (2 points) Write down the double silit formula here: Write down the n value for the first light Write down the n value for the second light n What variables on the right have the same value for this problem? Calculations (2 points) ??y, n..L-4 d__ (circle all that applies)

Explanation / Answer

double slit formula:

y=m*lambda*D/d

where y=distance of mth order bright fringe from central bright fringe

lambda=wavelength

D=distance of screen from the slits

d=slit width

part 2:

for the first light, n1=2

part 3:

for the second light n2=3

part 4:

y, L and d have the same value

calculations:

as distances are equal,

==>2*lambda_A*D/d=3*lambda_B*D/d

==>2*680 nm=3*lambda_B

==>lambda_B=453.33 nm

so unknown wavelength is 453.33 nm

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