Chapter 11, Problem 013 Interactive Solution 11.13 presents a model for solving

Question

Chapter 11, Problem 013 Interactive Solution 11.13 presents a model for solving this problem. A solid concrete block weighs 150 N and is resting on the ground. Its dimensions are 0.380 m x 0.170 m x 0.0540 m. A number of identical blocks are stacked on top of this one. What is the smallest number of whole bricks (including the one on the ground) that can be stacked so that their weight creates a pressure of at least two atmospheres on the ground beneath the first block? (Hint: First decide which face of the brick is in contact with the ground.) Number Units exact number, no tolerance Click if you would like to Show Work for this question: Qpen Show Work

Explanation / Answer

1 atm = 1.01325x105 Pa

2 atm = 2.0265x105 Pa

the greatest pressure from a block is if it is standing on the end with area, A

A = (0.380m)(0.0540m) = 0.02052m2

for 1 block F = 150 N

so 1 block has a pressure of P = F/A = 150N/0.02052m2 = 7310 Pa

divide the wanted pressure by the pressure of 1 block

2.0265x105Pa / 7310 Pa = 25.72

so you will need 26 blocks to make at least 2 Pa.

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