E PHYS 4A Homework 12 xy tri wileyPLUS x C In The Figure, A Square Of Edç Mathwa

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E PHYS 4A Homework 12 xy tri wileyPLUS x C In The Figure, A Square Of Edç Mathway | Math Problem Solve x tC Secure https://edugen.wileyplus.com/edugen/lti/main.uni Halliday, Fundamentals of Physics, 10e BACK NEXT ASSIGNMENT RESOURCES PCHYS 4A Homework12 Chapter 13 x Incorrect. hapter Probler In the figure, a square of edge length 19.0 cm is formed by four spheres of masses m1 = 5.20 g, m2 = 3.20 g, m3 = 1.00 g, and m4 = 5.20 g. In unit-vector notation, what is the net gravitational force from them on a central sphere with mass m5 = 2.70 g? 093 036 090 053 002 004 Nu Review Resul Stud Click if you would like to Show Work for this question: Open Show Work SHOW HINT GO TUTORIAL LINK TO TEXT LINK TO SAMPLE PROBLEM LINK TO SAMPLE PROBLEM VIDEO MINI-LECTURE MATH HELP Question Attempts: Unlimited SAVE FOR LATER SUBMIT ANSWER

Explanation / Answer

Gravitational force is given by:

F = G*m1*m2/R^2

Net force on the mass at Center will be zero due to m1 and m4, because m1 and m4 are equal and in opposite direction So they will cancel each other

Now due to m2 and m3 net force will be

Fnet = F2 - F3

Fnet = G*m2*m5/r^2 - G*m3*m5/r^2

r = distance b/w m2 and m5 = sqrt (0.095^2 + 0.095^2) = 0.134 m

Fnet = (G*m5/r^2)*(m2 - m3)

Fnet = (6.67*10^-11*2.70*10^-3/0.134^2)*(3.20*10^-3 - 1*10^-3) = 2.21*10^-14 N directed towards m2

In Unit-vector notation

Fnet = 2.21*10^-14*(cos 45 deg i + sin 45 deg j)

Fnet = 2.21*10^-14*cos 45 deg i + 2.21*10^-14*sin 45 deg j

Fnet = (1.56*10^-14 i + 1.56*10^-14 j) N

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